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Home/ Questions/Q 8726023
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T08:10:09+00:00 2026-06-13T08:10:09+00:00

I have the following Perl code: package CustomerCredit; #!/usr/local/bin/perl use 5.010; use strict; my

  • 0

I have the following Perl code:

package CustomerCredit;
#!/usr/local/bin/perl
use 5.010;
use strict;

my $TransRef = @_; # This code comes from a sub within the package.
my ($Loop, $TransArrRef, $TransID);
for ($Loop = 0; $Loop < $$#TransRef; $Loop++)
{
   $TransArrRef = $$TransRef[$Loop]; # Gets a ref to an array.
   $TransID = $$TransArrRef[0];  # Try to get the first value in the array.
   # The above line generates a compile time syntax error.
   ...
}

$TransRef is a reference to an array of references to arrays. I am trying to process each element in the array pointed to by $TransRef. $TransArrRef should obtain a reference to an array. I want to assign the first value within that array to $TransID. But, this statement generates a compile syntax error.

I must be doing something wrong, but can not figure out what it is. Can anyone help?

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  1. Editorial Team
    Editorial Team
    2026-06-13T08:10:10+00:00Added an answer on June 13, 2026 at 8:10 am

    The syntax error is coming from $$#TransRef which should be $#$TransRef. By misplacing the # you accidentally commented out the rest of the line leaving:

    for ($Loop = 0; $Loop <= $$
    {
       $TransArrRef = $$TransRef[$Loop];
       ...
    }
    

    $$ is ok under strict as it gives you the process id leaving the compiler to fail further down.

    Also, $#$TransRef gives you the last element in the array so you’d need <= rather than just <. Or use this Perl style loop:

    for my $loop (0 .. $#$TransRef) {
        $TransID = $TransRef->[$loop]->[0];
        #   ...
    }
    
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