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Home/ Questions/Q 8741281
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T11:17:03+00:00 2026-06-13T11:17:03+00:00

I have the following three queries SELECT COUNT(*) as cached_type_a, DATE(datetime) as datetime FROM

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I have the following three queries

SELECT COUNT(*) as cached_type_a, DATE(datetime) as datetime
    FROM requests
    WHERE cached = 'a'
    GROUP BY DAY(datetime);

SELECT COUNT(*) as cached_type_b, DATE(datetime) as datetime
    FROM requests
    WHERE cached = 'b'
    GROUP BY DAY(datetime);

SELECT COUNT(*) as cached_type_c, DATE(datetime) as datetime
    FROM requests
    WHERE cached = 'c'
    GROUP BY DAY(datetime);

Is it possible to combine them into a single query with 4 columns

cached_type_a, cached_type_b, cached_type_c, datetime?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T11:17:03+00:00Added an answer on June 13, 2026 at 11:17 am

    If you have only three possible values of cache, you can use this,

    SELECT DATE(datetime) as datetime,
            SUM(CASE WHEN cached = 'a' THEN 1 ELSE 0 END) cached_a,
            SUM(CASE WHEN cached = 'b' THEN 1 ELSE 0 END) cached_b,
            SUM(CASE WHEN cached = 'c' THEN 1 ELSE 0 END) cached_c
    FROM requests
    GROUP BY DAY(datetime)
    

    otherwise, if you have multiple number of cache, you can use Prepared Statement

    SET @sql = NULL;
    SELECT
      GROUP_CONCAT(DISTINCT
        CONCAT(
          'SUM(CASE WHEN cached =  ''',
          cached,
          ''' then 1 ELSE 0 end) AS ',
          CONCAT('cached_',cached)
        )
      ) INTO @sql
    FROM requests;
    
    SET @sql = CONCAT('SELECT DATE(datetime) as datetime, ', @sql, ' 
                       FROM requests 
                       GROUP BY DAY(datetime)');
    
    PREPARE stmt FROM @sql;
    EXECUTE stmt;
    DEALLOCATE PREPARE stmt;
    
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