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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T07:38:04+00:00 2026-05-27T07:38:04+00:00

I understand that function prototypes don’t need to have a name associated with the

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I understand that function prototypes don’t need to have a name associated with the parameters. For example:

void foo(int, std::string);

I was interested to find out recently that you could do the same thing in a function definition though:

void* foo(void*) { std::cerr << "Hello World!" << std::endl; }

Why does this work and how could you ever make use of an un-named parameter? Is there a reason this is allowed (like maybe dealing with legacy interfaces or something along those lines)?

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  1. Editorial Team
    Editorial Team
    2026-05-27T07:38:05+00:00Added an answer on May 27, 2026 at 7:38 am

    If you don’t intend to use the argument, then this is a good way of preventing compilers from warning you about it.

    This does indeed come up most often in the context of satisfying interfaces. For instance. you may be overriding a base-class method, but have no use for the parameters.

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