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Home/ Questions/Q 8125139
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T06:42:50+00:00 2026-06-06T06:42:50+00:00

I was reading some tutorial about openGL in qt. One of the mouse event

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I was reading some tutorial about openGL in qt.
One of the mouse event slot has this code in it:

if (event->buttons() & Qt::LeftButton) {    
    rotationX += 180 * dy;
    rotationY += 180 * dx;
    updateGL();
}

what does the & operator do in the if statement?
is it exactly the same as == ?

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  1. Editorial Team
    Editorial Team
    2026-06-06T06:42:53+00:00Added an answer on June 6, 2026 at 6:42 am

    It is not the same as ==. It is bitwise AND operator. What the expression does is that it takes the return value from event->buttons() and bitwise AND‘s it with the value represented by Qt::LeftButton. If the resulting value is non-zero the block is being executed.

    In essence, it checks if the button specified by Qt::LeftButton is held down.

    The reason why the bitwise AND operator is used here is something called a bitmask. What it means is that the return value of event->buttons() is just a value which has it’s bits represent different kinds of states. What is done with the &-operator here is that it checks if certain bits(denoted by Qt::LeftButton) are being set(1) or unset(0) in the value returned by event->buttons(). The return value is zero if no tested bit is set, and non-zero, if at least one of the tested bits is set.

    More details of how bitwise operations work can be found here: Wikipedia article about Bitwise operations

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