Question

If I want the path of the current module, I’ll use __file__.

Now let’s say I want a function to return that. I can’t do:

def get_path():
    return __file__

Because it will return the path of the module the function has been declared in.

I need it to work even if the function is not called at the root of the module but at any level of nesting.

Answer 1

This is how I would do it:

import sys

def get_path():
    namespace = sys._getframe(1).f_globals  # caller's globals
    return namespace.get('__file__')