Question

if($a == 4){
echo ‘ok’;
}

Now displays an error because $a variable is not defined.
my decision:

if(isset($a)){
    if($a == 4){
    echo 'ok';
    }
}

But maybe there are better solutions?

Answer 1

I think it’s good enough. You could merge the two ifs if you like.

if (isset($a) && $a == 4) {
  echo 'ok';
}