Question

Say I assigned an array like so:

char* array[]={"This"};

And then later I wanted to assign array[ ] a new value so that it stores “This” and “That,” is there a way that I could change the size of array so that it could hold a new number of values?

Answer 1

No, you can’t change the size of an array. You could use a dynamically allocated list of char* instead and realloc() as required:

#include <stdlib.h>
#include <string.h>
#include <stdio.h>

int main() {
    char** array = malloc(1 * sizeof(*array));

    if (array) {
        array[0] = "This";

        printf("%s\n------\n", array[0]);

        char** tmp = realloc(array, 2 * sizeof(*array));
        if (tmp) {
            array = tmp;
            array[1] = "That";

            printf("%s\n", array[0]);
            printf("%s\n", array[1]);
        }

        free(array);
    }
    return 0;
}

See online demo: https://ideone.com/ng00k.