Question

Say I have the following:

Foo* foo = new Foo(bar);

//later on
*foo = Foo(anotherBar);

Since foo was allocated on the heap does this cause problems or will the memory from the temporary Foo be copied into the address of foo on the heap?

Thanks

Answer 1

*foo = Foo(anotherBar); is no different than a regular assignment to an object of Foo type. *foo returns an lvalue of type Foo, and you are assigning to it.

Short answer: it won’t cause problems, the temporary will be copied into the heap Foo object pointed by foo.