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Home/ Questions/Q 1003907
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T08:03:03+00:00 2026-05-16T08:03:03+00:00

So suppose I have a tree class like this in c++ class Node{ void

  • 0

So suppose I have a tree class like this in c++

class Node{
    void addChild(Node*);
    /*obvious stuff*/
    protected:
        Node* parent;
        vector<Node*> children
}

class specialNode : public Node{
    void addChild(specialNode*);
    /*obvious stuff*/
    /*special stuff*/
}

Now whenever I access the children in specialTree, I obviously get Node*, not specialNode*.

But this specialNode* has member variables and functions that Node doesn’t have.

I can force specialNode to only have take specialNode as children and otherwise break in compile time,
but I still get Node* when accessing children/parent, and I have to cast it whenever I want to use special functions, even in specialNode functions.

Is there any clever, or just any better way to go about this?
Other than literally casting every time?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T08:03:04+00:00Added an answer on May 16, 2026 at 8:03 am

    If you only need SpecialNode objects in your tree (and just want to encapsulate all generic tree functionality in Node) you can make Node a so called “mix-in” class like

    template <class N>
    class Node : public N {
    public:
      void addChild(Node<N>*);
    protected:
      Node<N>* parent;
      vector<Node<N>*> children;
    };
    
    class SpecialNodeBase {
      // Here comes all "special" data/methods for your "special" tree
    };
    
    typedef Node<SpecialNodeBase> SpecialNode;
    

    After that you can construct a tree of SpecialNode objects and use all methods from SpecialNodeBase as well as additional tree-managing functions from Node

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