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Home/ Questions/Q 8724433
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T07:49:49+00:00 2026-06-13T07:49:49+00:00

struct Vertex{ int num; int low; bool seen; Vertex *parent; Vertex(){ num = 0;

  • 0
struct Vertex{
    int num;
    int low;
    bool seen;
    Vertex *parent;
    Vertex(){
        num = 0; low = 0; seen = false; parent = NULL;
    }
};

This is the struct. The problem is that when i attempt to make an array of type Vertex, the debugger states it’s of non-pointer class type. This is how I declare it:

Vertex *mark;
mark = new Vertex[numVert];

(mark is declared in the class and the assignment is done in the default constructor).

I’ve declared pointer arrays exactly like this before. What would be the reason that it does not work now?

Graph::Graph(int v){
int i;
numVert = v;
count = 0;
mark = new Vertex[numVert];
matrix = new int*[numVert];
for (i=0;i<numVert;i++){
    mark[i]->seen = false;
    matrix[i] = new int[numVert];
    for (int j=0; j<numVert;j++)
        matrix[i][j]=0;
    }
}

This is where it is initially called. It states that it’s of non-pointer type on both the assignment of the array and the assignment of its ‘seen’ member to false.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T07:49:51+00:00Added an answer on June 13, 2026 at 7:49 am

    The line

    mark = new Vertex[numVert];
    

    Allocates numVert objects in memory (calling the default constructor for each) and returns the address of the first object.
    In that regard your code is completely legit.

    The debugger says that the object mark points to is not a pointer, which is correct (it’s an array of objects).

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