Question

sTypeName = ... //do some string stuff here to get the name of the type

/*
The Assembly.CreateInstance function returns a type
of System.object. I want to type cast it to 
the type whose name is sTypeName.

assembly.CreateInstance(sTypeName)

So, in effect I want to do something like:

*/

assembly.CreateInstance(sTypeName) as Type.GetType(sTypeName);

How do I do that? And, what do I take on the left side of the assignment expression, assuming this is C# 2.0. I don’t have the var keyword.

Answer 1

Usually you let all classes, you want to instantiate this dynamically, implement a common interface, lets say IMyInterface. You can create an instance from the classname string like this:

Assembly asm = Assembly.GetExecutingAssembly();
string classname = "MyNamespace.MyClass";
Type classtype = asm.GetType(classname);

// Constructor without parameters
IMyInterface instance = (IMyInterface)Activator.CreateInstance(classtype);

// With parameters (eg. first: string, second: int):
IMyInterface instance = (IMyInterface)Activator.CreateInstance(classtype, 
                        new object[]{
                            (object)"param1",
                            (object)5
                        });

Even if you dont have a common interface, but know the name of the method (as string) you can invoke your methods like this (very similar for properties, event and so on):

object instance = Activator.CreateInstance(classtype);

int result = (int)classtype.GetMethod("TwoTimes").Invoke(instance, 
                        new object[] { 15 });
// result = 30

The example class:

namespace MyNamespace
{
    public class MyClass
    {
        public MyClass(string s, int i) { }

        public int TwoTimes(int i)
        {
            return i * 2;
        }
    }
}