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Home/ Questions/Q 8055815
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T08:30:38+00:00 2026-06-05T08:30:38+00:00

While I do understand why there is no operator== for shared_ptr and unique_ptr ,

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While I do understand why there is no operator== for shared_ptr and unique_ptr, I wonder why there is none for shared_ptr and weak_ptr. Especially since you can create a weak_ptr via a reference on shared_ptr.
I would assume that for 99% of the time you want lhs.get() == rhs.get(). I would now go forward and introduce that into my code unless someone can name me a good reason, why one should not do such a thing.

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  1. Editorial Team
    Editorial Team
    2026-06-05T08:30:40+00:00Added an answer on June 5, 2026 at 8:30 am

    weak_ptr doesn’ have a get() method because you need to explicitly lock the weak_ptr before you can access the underlying pointer. Making this explicit is a deliberate design decision. If the conversion were implicit it would be very easy to write code that would be unsafe if the last shared_ptr to the object were to be destroyed while the underlying pointer obtained from the weak_ptr was still being examined.

    This boost page has a good description of the pitfalls and why weak_ptr has such a limited interface.

    If you need to do a quick comparison, then you can do shared == weak.lock(). If the comparison is true then you know that weak must still be valid as you hold a separate shared_ptr to the same object. There is no such guarantee if the comparison returns false.

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