Question

I have function foo take jquery wrapped node as an argument. Is there more elegant way to run this function on nodes set?

The way I do it:

$('.for-foo').each(function () {
    foo($(this));
});

Answer 1

You can make it a plugin:

$.fn.foo = function(){
  return this.each(function(){
    // do something to each element "this"
  });
};

Usage:

$('.for-foo').foo();

This will also make it chainable with other jQuery functions.